What are the three primary lamp/bulb energies used in a Photoionization Detector (PID)?

Prepare for the TEEX Hazardous Materials Technician exam with real-life scenarios and practice questions. Master the competencies needed for successful certification and excel in hazardous materials response.

A Photoionization Detector (PID) is an instrument used to detect and measure volatile organic compounds (VOCs) and other gases by utilizing ultraviolet light. The primary function of the PID is to ionize gas molecules, which allows for their detection based on the resulting electrical current.

The three primary lamp/bulb energies are crucial because they determine the types of compounds that can be effectively ionized and detected. Each energy level has a specific ionization potential, meaning that the energy must be sufficient to ionize target molecules but not so high that it causes unnecessary ionization of background gases.

The chosen answer presents the typical energies that align with the sensitivity and effectiveness needed to ionize a wide range of organic compounds. Energies of 9.8 eV, 10.6 eV, and 11.7 eV cover a significant threshold for various VOCs, making the PID highly effective for detecting these substances at low concentrations.

Choosing this set of energy levels allows for a balance of sensitivity and specificity in readings, allowing the PID to differentiate between various gases effectively. This selection is commonly found in the specifications for many PIDs used in environmental monitoring and hazardous material response scenarios.

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